Simplifying madly (and probably dropping the odd decimal place here and there), this is how I went about it.
- Imagine a sphere as big as the earth's orbit round the sun: the sun at its centre and a radius of 150 million kilometres.
- Think of the earth as a circle on the surface of that sphere: a radius of 6370 kilometres.
- The surface area of the big sphere is 283 quadrillion (282,743,338,823,081,391) km2.
- The area of the "earth disc" is 127 million km2.
- Which is 0.000000045% of the surface area of the big sphere.
- OK, that's meaningless, so how do we translate it into terms that people might understand?
- Start with a standard football and imagine it with a tiny sun at its centre and the earth disc on its surface.
- But that makes earth really, really tiny, and I couldn't find out the area of a pin point.
- So move up a bit: imagine the earth with a tiny sun at its centre and the "earth disc" on its surface.
- A few sums later, and I determine that the earth disc has an area of 230,000 m2.
- Which is 32 football pitches, and everybody understands that.
- But the basic truth is that the amount of the sun's light that can ever hit the earth is less than half of one ten-millionth of one per cent.
Does that help?